Pokémon TCG: Sword and Shield—Brilliant Stars

Is there anywhere to get odds?

Wrightma

New Member
How can i find out how rare certain poemon cards are in regards to odds per booster pack, or does this not exist?
 
I'm not quite sure what you're asking, but I think the average per booster box for a prime is 3 (not 100% sure), so because there are 36 packs in a Booster Box it is about 1 in 12 packs will have a prime. Sorry if that's not what you're asking though, I had a little trouble understanding your first post.
 
Are you talking about how rare a card is in a ratio of card to box? If so then there is no set number. If so, it depends on the specific card and even then, there is no way to know how many of a card you will get.
 
I'm not quite sure what you're asking, but I think the average per booster box for a prime is 3 (not 100% sure), so because there are 36 packs in a Booster Box it is about 1 in 12 packs will have a prime. Sorry if that's not what you're asking though, I had a little trouble understanding your first post.

Yet somehow we get 5-6 primes per box :rolleyes:
 
yeah, it depends 1) the rarity of the card, 2) how many of that rarity are in that set, 3) how big the set is, and im sure P!P has some VooDoo ritual they preform while making the cards which allows them to determine which cards are going to be the most sought after and make them harder to get. like i pulled 5 primes in my box of triumphhant, only two shinings in my call of legends box (worst mistake ive made while in competitive play, btw), and 1 full art reshi and 1 fa zek and one sr pikachu in my b/w box all have the same rarity but different numbers.
 
Do the math yourself. Lets check it real fast like, using B&W as an example:

115 cards in the set

1 Secret Rare
2 Ultra Rare
31 Rare (12 of which are holo)
38 Uncommon
43 Common

You get:
5 common
3 Uncommon
1 Rare
1 RH

The math get fairly complicated due to RH's, but, keeping it simple:

5 Common/pack-43 common/set

So, the probability on that is as such:

The odds of pulling a Pansage 7/114:

The probability of the first common NOT being Pansage: 42/43
The probability of the second common NOT being Pansage: 41/42....and so on:

42/43 = 97.7%
41/42 = 97.6%
40/41 = 97.6%
39/40 = 97.5%
38/39 = 97.4%

97.7%*97.7%*97.6%*97.5%*97.4%= 88.4% you DO NOT pull Pansage.

100-88.4= 11.6% chance you DO pull Pansage. So, there is an 11.6% chance to pull any common. In all reality, its a bit different due to RH's, but that is a good starting point.

Use the same logic for Uncommon's and Rares.

As for Ultra Rares and Secret Rares, I don't think there is a set in stone way of calculating them other than to just look at ratios of boxes. From what I've seen, every box yields two Ultra Rares, and about 2.5 boxes per Secret Rare. So, the math on that is pretty simple:

36 packs/box
2 Ultra Rare/box
1 Ultra Rare about every 18 packs
~6%

36 packs/box
1 Secret Rare~2.5 boxes (I've heard 2 and 3, 2.5 seems safe)
1 Secret Rare about every 90 packs
~1%
 
The math get fairly complicated due to RH's, but, keeping it simple:

5 Common/pack-43 common/set

So, the probability on that is as such:

The odds of pulling a Pansage 7/114:

The probability of the first common NOT being Pansage: 42/43
The probability of the second common NOT being Pansage: 41/42....and so on:

42/43 = 97.7%
41/42 = 97.6%
40/41 = 97.6%
39/40 = 97.5%
38/39 = 97.4%

97.7%*97.7%*97.6%*97.5%*97.4%= 88.4% you DO NOT pull Pansage.

100-88.4= 11.6% chance you DO pull Pansage. So, there is an 11.6% chance to pull any common. In all reality, its a bit different due to RH's, but that is a good starting point.

Use the same logic for Uncommon's and Rares.

Everyone probably knows this but keep in mind that these are just odds and are not guaranteed. You could always get better or worse odds either way. Like back when MD came out I got two boxes and only got one Spearow (a common) out of both boxes combined. :mad: Someone do the odds for that. :lol:
 
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