I`ve done some investigation and calculation with some really difficult formulas I foun on the web to come with an acceptable number of heads to be flipped in a row. I took in acount that most coinsare heavier at the heads side, that the chances that you `ll flip heads are bigger when you place heads face up at the begining of the flip (it`s true, nice trick) and I used the ( a bit to high:redface: but else I wouldn`t top the current highestdamage, and it`s possible after all)number of 33554432 coin flips (2^25) that an average pokemon TCG player flips in his TCG carier.
If i`haven`t made any mistakes there will be 1 time in your pokemon carrier where you`ll flip 44,356178 =44 heads in a row
!!! (chances are I`ve made a mistake though, lol) (If you want to calculate it for yourself Use this formula and make several adjustments for the tricks and weight differences:
nCr*p^r*q^(n-r)+L
The C being on your calculator as nCr
n=number of trials
r=number of successes (achieveing a heads)
p=probability of success
q=probability of failure
L= luck, you`ll need it ;P)
So, that said...heres the situation
You use Steelix SF and flip 44 heads = 4400
You play 4 plus power = +40
You play 1 buck = +10
The defending pokemon is Glaceon lvl X so everything prementioned is * 2 =4400+40+10 *2 =8900
The defending pokemon was Burned by Magmortar lvl X (and of course its heads) = +30
The defending pokemon was poisoned by Drapion Lvl X = +30
Armaldo has used his attack during you last turn = +40
You play 4 Crobat G = +40
You have attached a Energy to Raikou SW = +10
Cresselia Lvl X swapped 1 damge counter to the defending pokemon = +10
To make all of this possible I`ve used poketurns and SSU`s wich all miraculously were heads....
=9060
....hope I didn`t make too many mistakes...