Pokémon TCG: Sword and Shield—Brilliant Stars

Riddle

Here's an old one for everyone...

I have two coins in my hand that total exactly 30 cents. One of them is not a nickel, what are the two coins?
 
Ok, A Group Of Colours Includes:
Red
White
Black
Blue
Pink
Brown

There Are Two Other Colours That Belong To This Group, But What Are They?
 
Here's a very old one you may or may not have heard. It's called "The Puzzle of the Jealous Husbands." The only change I made was to give the characters names -- the structure of the puzzle, as well as the solution, is unchanged.

Adam and his wife Betty, Charles and his wife Diane, and Emilio and his wife Felicity (note: I purposely chose these names in alphabetical order, to make it easier to know who's who) are all traveling together, when they come to a river. The good news is that there is a boat available which can hold a maximum of 2 people. Unfortunately, Adam, Charles, and Emilio don't completely trust each other. In fact, none of the men are willing to have their wives be in the presence of any of the other men unless the husband is also present. For example, Emilio won't leave Felicity in Adam's and/or Charles' company unless he's there. Under these constraints, find a way for all of them to cross the river. Note that the boat is the only way across, and the jealousy constraint applies to being on the same side of the river and to being in the boat. Note also that nobody has a problem with two (or all three) women being together without any husbands. My one hint to you is that the shortest possible solution involves 11 separate crossings of the river.
 
Marril: GHOTI = fish

- GH makes the "f" sound, like in "cough"
- O makes the "i" sound, like in "women"
- TI makes the "sh" sound, like in "caption"

dkates: I think I got this one too...

1. Adam and Betty cross
2. Adam returns
3. Diane and Felicity cross
4. Betty returns
5. Charles and Emilio cross
6. Emilio and Felicity return
7. Adam and Emilio cross
8. Diane returns
9. Betty and Diane cross
10. Emilio returns
11. Emilio and Felicity cross
 
Adam and his wife Betty, Charles and his wife Diane, and Emilio and his wife Felicity problem:

ACEF|---->BD>----|
ACEF|----<B<----|D
ACE|---->BF>----|D
ACE|----<B<----|DF
AB|---->CE>----|DF
AB|----<EF<----|CD
BF|---->AE>----|CD
BF|----<D<----|ACE
B|---->DF>----|ACE
B|----<A<----|CDEF
|---->AB>----|CDEF

...at which point everyone is over :)
 
I may have to double-check later, but I think that TheDeuce and KayLynn both got working solutions to the Jealous Husbands problem. To check, just look at each step and make sure that you're within the jealously constraint.
 
A detective walks into an alley, and he sees a corpse with a gun and a tape recorder next to it. Hoping to find evidence, the detective presses the play button on the recorder. The recorder says, "This world is too screwed up, I'm ending it now!!!!" followed by a gunshot. The detective files a case for murder instead of suicide. Why?
 
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While I was going to St Ives, I met a man with seven wives. Each wife had seven sacks, each sack had seven cats, each cat had seven kits. Me, him, wives, sacks, and kits, how many were going to St Ives?
 
Marril said:
While I was going to St Ives, I met a man with seven wives. Each wife had seven sacks, each sack had seven cats, each cat had seven kits. Me, him, wives, sacks, and kits, how many were going to St Ives?

1. You.

I can only think of a simple one at the moment: x*x=x+x. There are two possible values of X to make this true. What are they?
 
In answer to Artic's: The tape played the gunshot and yet apparently did not require rewinding. Since the gunshot would have, in theory, killed the guy, someone else must have rewound the tape. Thus, the man was shot by someone else, a tape was faked, and left by the body.
And in answer to Orange Soda's: 2 and 0
 
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Orange Soda said:
1. You.

I can only think of a simple one at the moment: x*x=x+x. There are two possible values of X to make this true. What are they?
3 times 2 = 6
& 3 + 3 = 6?

:confused: :confused: :confused: :confused: :confused:
If i'm right, :thumb:
if not, :confused: :( that's ok!
 
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Marril: - Just one, yourself.

Charizard: - There's like 20 different answers to this, I'm just gonna say "a newspaper"


Zack wants to get into a very exclusive club, but he is not a member. Each member kows the passcode to get into the club, and has to tell it to the bouncer in order to be let in. Zack decides that he is going to try and sneak in, so he hides in a bush near the club, and watches. After about 10 minutes a member walks up, the bouncer says "six" the member says "three" and the bouncer lets him in. A little later another member walks up, the bouncer says "twelve" and the member replies "six", the bouncer lets him in as well. Zack thinks that he's figured it out so he walks up to the bouncer, the bouncer says "ten" and Zack replies "five", the bouncer throws Zack out. What should Zack have said to get into the club, and why?
 
I think he should have said three.
six has three letters in it so the first member said three
twelve has six letters in it so the second member said six
ten has three letters so Zack should have said three
 
No One Has Even Guessed At Mine (The Colours One).

I'll Give You A Clue, I't Somthing To Do With A Sport. I'm Not Sure How Popular This Sport Is In The U.S Or Canada, But You Should Have Heard Of It.
 
Mr. Grass said:
In answer to Artic's: The tape played the gunshot and yet apparently did not require rewinding. Since the gunshot would have, in theory, killed the guy, someone else must have rewound the tape. Thus, the man was shot by someone else, a tape was faked, and left by the body.
And in answer to Orange Soda's: 2 and 0
Correct, sorry for the late post, but my comp got hit my a worm a week ago.

Anyway here's another one. You are traveling to a town and come to a fork in the road, at the fork are two boys, one you know will always tell the truth and one who always lies. You have to ask one question to the boys to know which path to take. You do not know which boy is which and you must ask them the same question.

There are several answers to this riddle.
 
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